simple coding job

[DeXTeRLaB]

Hey fellows, Who can write me 1 line of code or solve to convert following:


I have list of dates in this format:
* Day/Month/Year

92060
111458
70149


i need in this format..
DD/MM/YYYY
09/20/1960
11/14/1958
07/01/1949

$$ for this! Fast Job 5 mins

 

[pa127]

Php, c, perl, python?

 

[aberkroft]

Ugly case for lazy evening, but

line="91258";if [[ ${#line} -eq 5 ]]; then line="0$line"; fi; echo -n "${line:0:2}/${line:2:2}/19${line:4:2}"

(for Linux bash)

and the same for stdin reading

while IFS= read -r line; do if [[ ${#line} -eq 5 ]]; then line="0$line"; fi; echo -n "${line:0:2}/${line:2:2}/19${line:4:2}"; echo ""; done

or from file

while IFS= read -r line; do if [[ ${#line} -eq 5 ]]; then line="0$line"; fi; echo -n "${line:0:2}/${line:2:2}/19${line:4:2}"; echo ""; done << data.txt

 

[tixepok]

in_f = open("in.txt", "r")
out_f = open("out.txt", "w")
line = in_f.readline()
while line:
    line = line.strip()
    day = int(line[-6:-4])
    out_f.write("%02d/%s/19%s\n" % (day, line[-4:-2], line[-2:]))
    line = in_f.readline()
in_f.close()
out_f.close()

 

[DeXTeRLaB]

Thanks all! Solved.